Question

Rezolvaţi ecuațiile în mulţimea numerelor reale:
a) 5x + 9 + 3(2x - 1) = 2x + 24;
b) 7x + 8 – 2(x - 5) = 6 + 2(x + 3);
c) 4x + 7 + 5(x + 3) = 2x + 1;
d) 4(x + 3) - 205 - x) = 3x + 11;
e) 3x + 9 + 2(3 - x) = 4 + 2(x + 5); f) 2(5x - 3) + 4x - 3(7 - 2x) = 5(3x + 1) + 8;
g) 5(2x - 3) + 3(5x-6) + 13 = 8(3x + 7) - 63;
h) 7(4x - 3) - 4(3x + 8) + 25 = 3(4x +9) - 43;
i) 3(4x - 5) - 3(2x + 7) + 32 = 2(2x + 1) - 14;
j) 6(x + 3) - 3(x + 1) + 5 =-3x - 2(2x + 5);​

Answer 1

Răspuns:

Explicație pas cu pas:

5x+9+6x-3-2x-24=0

9x-18=0

9x=18

x=18/9

x=2

b) 7x+8-2x+10-6-2x-6=0

3x-6=0

3x=6

x=6:3

x=2

c) 4x+7+5x+15-2x-1=0

7x+21=0

7x=-21

x=-21:3

x=-7

d)?

e) 3x+9+6-2x-4-2x-10=0

-x+1=0

-x=-1/*-1

x=1

f) 10x-6+4x-21+6x-15x-5-8=0

5x-40=0

5x=40

x=40:5

x=8

g) 10x-15+15x-18+13-24x-56+63=0

x-13=0

x=13

h) 28x-21-12x-32+25-12x-27+43=0

4x-12=0

4x=12

x=12:4

x=3

i) 12x-15-6x-21+32-4x-2-14=0

2x-20=0

2x=20

x=20:2

x=10

j) 6x+18-3x-3+5+3x+4x+10=0

10x=30

x=30:10

x=3

Answer 2

Răspuns:

Sper acuma să fie bine...te rog frumos sa imi spui...Bafta