Question

Rezolvati ecuațiile........mulțumesc mult

Answer 1

$\frac{6x}{5}-x=\frac{x}{3}+8x$ <=> 18x-30x=5x+240x <=> 257x=0 <=> x=0

s)

$\frac{1}{4}*${${\frac{1}{4}*[\frac{1}{4}*(\frac{1}{4}*x+1)+4]+1$}+4=5 <=> $\frac{1}{4}*[\frac{1}{4}*(\frac{1}{4}*\frac{x+4}{4}+4)+1]+4=5$ <=> $\frac{1}{4}*(\frac{1}{4}*\frac{x+4+64}{16}+1)+4=5$ <=> $\frac{x+4+64+64+4*256}{256}=5 <=> \frac{x+1156}{256}=5 <=> x=124$

t)

0,(6)*x+2x-0,(3)=4-2(x+1)+3,(6) <=> $\frac{6}{9}*x+2x-\frac{3}{9}=4-2x-2+\frac{33}{9}$ <=> 6x+18x-3=18-18x+33 <=> 42x=54 <=> $x=\frac{54}{42}=\frac{9}{7}$