Question

Rezolvați ecuațiile. Mulțumesc mult !!

Answer 1

Salutare!

e)

$\bf \dfrac{x}{3}- \dfrac{x-3}{4}= \dfrac{x+1}{6}\:\:|\cdot 24$

$\bf 24\cdot\dfrac{x}{3}- 24\cdot\dfrac{x-3}{4}=24\cdot \dfrac{x+1}{6}$

$\bf \not24\cdot\dfrac{x}{\not3}- \not24\cdot\dfrac{x-3}{\not4}=\not24\cdot \dfrac{x+1}{\not6}$

$\bf 4\cdot x- 3\cdot(x-3)=2\cdot(x+1)$

$\bf 4x- 3x+9=2x+2$

$\bf x+9=2x+2$

$\bf 9=2x-x+2$

$\bf 9=x+2$

$\bf 9-2=x$

$\boxed{\bf x=7}$

j)

$\bf \dfrac{2}{5}\cdot \Big( \dfrac{5}{4}x- \dfrac{5}{6}\Big)= 3x-\dfrac{1}{6}$

$\bf \dfrac{2}{5}\cdot \dfrac{5}{4}x- \dfrac{2}{5}\cdot\dfrac{5}{6}= 3x-\dfrac{1}{6}$

$\bf \dfrac{\not2}{\not5}\cdot \dfrac{\not5}{\not4}x- \dfrac{\not2}{\not5}\cdot\dfrac{\not5}{\not6}= 3x-\dfrac{1}{6}$

$\bf \dfrac{1}{1}\cdot \dfrac{1}{2}x- \dfrac{1}{1}\cdot\dfrac{1}{3}= 3x-\dfrac{1}{6}$

$\bf \dfrac{x}{2}-\dfrac{1}{3}= 3x-\dfrac{1}{6}\:\:\:|\cdot6$

$\bf 3x-2=18x-1$

$\bf 3x=18x-1+2$

$\bf 3x=18x+1$

$\bf 3x-18x=1$

$\bf -15x=1$

$\boxed{\bf x=-\dfrac{1}{15}}$

Answer 2

Salutare! Am ataşat rezolvarea. :)