Question

Rezolvati ecuatiile :
$2 \frac{3}{8} ( \frac{1}{3} -3x)+ \frac{5}{8 } ( \frac{1}{3} - 3x) =1$

Answer 1

$\frac{19}{8} * \frac{1}{3} - \frac{19}{8} * 3x+ \frac{5}{24} - \frac{5}{8} *3x=1 \\ 19-19*3x*3+5-5*3x*3=24 \\ 19-171x+5-45x=24 \\ -216x=0 \\ x=0$

Answer 2

[tex]2 \frac{3}{8}( \frac{1}{3}-3x)+ \frac{5}{8}( \frac{1}{3}-}3x)=1 \\ \\ ( \frac{1}{3}-^{3)}3x)( \frac{19}{8}+ \frac{5}{8}) = 1 \\ \\ (\frac{1}{3}- \frac{9x}{3})* \frac{24}{8}=1 \\ \\ \frac{1-9x}{3}*3=1 \\ \\ 1-9x=1 \\ \\ 9x=0 \Longrightarrow \boxed{x=0}[/tex]