Question

Rezolvati ecuatiile: x+23,5+1,02=100; (2x-1)*2,5=14,7; $0,1^{2}$*$2,3^{2}$*$10^{4}$-x=2; [(1,5+x)*2+1,3]=10; {[52-(4,5*x+1)+3,4]/2+22}*3=144
Va rog ajutati-ma!!!

Answer 1

x+23,5+1,02=100
x+24,52=100
x=100-24,52
x=75,48

 (2x-1)·2,5=14,7
5x-2,5=14,7
5x=14,7+2,5
5x=17,2
x=172/10:5
x=172/50=86/25=3,44
x=3,44

0,1²·2,3²·10⁴-x=2
0,01·5,29·10000-x=2
529-x=2
-x=-529+2
-x=-527      inmultim -1
x=527

[(1,5+x)·2+1,3]=10
3+2x+1,3=10
2x=10-1,2-3
2x=5,8
x=5,8/2
x=2,9

{[52-(4,5x+1)+3,4]/2+22}·3=144
{[52-4,5x-1+3,4]/2+(22·2)/2}·3=144
(-4,5x+54,8+44)/2=144:3
(-4,5x+98,8)/2=48
-4,5x+98,8=48·2
-4,5x=96-98,8
-4,5x=-2,8    inmultim -1
x=2,8/4,5
x=0,6(2)

Answer 2

x+23,5+1,02=100
x+23,5=100-1,02
x+23,5=98,98
x=98,98-23,5
x=75,48
0,1² * 2,3² * 10²×² - x = 2
0,01 * 5,29 * 10000 - x =2
0,0529 * 10000 - x =2
529 - x =2
x= 529-2
x=527
[(1,5+x) *2+1,3]=10
(1,5+x) *2=10-1,3
(1,5+x)*2=8,7
1,5+x=8,7:2
1,5+x=4,35
x=4,35-1,5
x=2,85 
{[52-(4,5*x+1)+3,4]/2+22}*3=144
[52-(4,5*x+1)+3,4]:2+22=144:3
[52-(4,5*x+1)+3,4]:2+22=48
[52-(4,5*x+1)+3,4]:2=48-22
[52-(4,5*x+1)+3,4]:2=26
52-(4,5*x+1)+3,4=26*2
52-(4,5*x+1)+3,4=52
52-(4,5*x+1)=52-3,4
52-(4,5*x+1)=48,6
4,5*x+1=48,6+52
4,5*x+1=100,6
4,5*x=100,6-1
4,5*x=99,6
x=99,6:4,5
x=22,1(3)