Question

rezolvati ecuatile 4(supra)3x-2=1(supra)3 (x+4) și 10x-1,2=x(1,4+5) Va roggggggggg

Answer 1

1. $\frac{4}{3x-2}=\frac{1}{3(x+4)}$
$\frac{4}{3x-2}=\frac{1}{3x+12}$⇒[tex]4(3x+12)=3x-2 12x+48=3x-2 9x=-50 [/tex]⇒$x=-\frac{50}{9}$

2. [tex]10x-1.2=x(1.4+5) 10x-1.2=6.4x 10x-6.4x=1.2 3.6x=1.2 x=0.(3)[/tex]