Question

rezolvati ekuatia)))))​

Answer 1

Răspuns:

Conditiile   de   existenta  ale   radicalilor

x+1≥0

x≥ -1

9-x≥0

x≤9

2x-12≥0

x-6≥0

x≥6

x∈[-1,+∞)∩(-∞,9]∩[6,+∞)=[6,9]=DVA

Ridici   ecuatia   la  patrat

x+1+9-x-2√(x+1)(9-x)=2x-12

10-2√(x+1)(9-x)=2x-12

-2√(9x+9-x²-x)=2x-22║:2

-√(-x²+8x+9)=x-11

Ridici  relatia   la  patrat

-x²+8x+9=x²-22x+121

-2x²+30x-112=0:║:(-2)

x²-15x+56=0

x1=7∈DVA

x2=8∈DVA

Explicație pas cu pas: