Question

Rezolvati exercitiile va rog
(2x+7)²=
(2x+5y)²=
(1pe 2x-7)²=
(3x-7y)²=
(1pe 3x+7) (1pe3x-7)
(√3-√5)²=
(24√7)²=
(√7-√3)(√7+√3)=
Va rog !!!

Answer 1

f)


a)
(2x+7)²
(2x)²+2*2x*7+7²
4x²+28x+49

b)
(2x+5y)²
(2x)²+2*2x*5y+5y)²
4x²+20xy+25y²

d)
(3x-7y)²
(3x)²-2*3x*7y+(7y)²
9x²-42xy+49y²

f)
(√3-√5)²
(√3)²-2*√3*√5+(√5)²
3-2√15+5
8-2√15

(24√7)²
24²*(√7)²
576*7
4032

(√7-√3)(√7+√3)
√7(√7+√3)-√3(√7+√3)
√49+√21-√21-√9
(+√21 cu -√21 s ereduc si ne da 0)
7-3
4

scz ca nu le-am facut pe toate