Question

Rezolvați exercițiul:1000-[(2+3x9:1)+(200+100)]=?

Answer 1

1000-[(2+3·9:1)+(200+100)]=
1000-[(2+27)+300]=
1000-(29+300)=
1000-329=671

Raspuns: 671

Answer 2

1000-[(2+3×9:1)+(200+100)] =
=1000-[( 2+27:1)+300]=
=1000-[(2+27)+300]=
=1000- (29+300)=
=1000-329=
=671