Question

Rezolvati exercitiul.

Answer 1

$a).(3 \frac{1}{2} - \frac{1}{2} )+(1 \frac{1}{3} - \frac{1}{3} )=( \frac{7}{2} - \frac{1}{2} )+( \frac{4}{3} - \frac{1}{3} )= \frac{6}{2} + \frac{3}{3} =3+1=4 \\ \\ b). \frac{3}{14} ( \frac{7}{8} * \frac{8}{3} +3 \frac{1}{3} *2 \frac{1}{10} )= \frac{3}{14} ( \frac{56}{24} + \frac{10}{3} * \frac{21}{10} )= \frac{3}{14} ( \frac{56}{24} + \frac{210}{30} )= \\ \\ = \frac{3}{14} ( \frac{280}{120} + \frac{840}{120} )= \frac{3}{14} * \frac{1120}{120} = \frac{3360}{1680} =2$

$c).3:(2 \frac{3}{4} -1 \frac{15}{28} )+ \frac{2}{3} : \frac{3}2} =3:( \frac{11}{4} - \frac{43}{28} )+ \frac{2}{3} * \frac{2}{3} =3:( \frac{77}{28} - \frac{43}{28} )+ \frac{4}{9} = \\ \\ =3: \frac{34}{28} + \frac{4}{9} =3* \frac{28}{34} + \frac{4}{9} = \frac{84}{34} + \frac{4}{9} = \frac{42}{17} + \frac{4}{9} = \frac{378}{153} + \frac{68}{153} = \frac{446}{153}$