Question

rezolvati exercitiul 13 ;)

Answer 1

A={1;2}
Efectuand calculele obtinem 1²=1; 2²=4; 1³-1=0 ;2³-1=8-1=7
deci
B={1;4}
C={0;7}


Atunci
a)A∪B={1;2;4}
B∩C=∅
(A∪B)\∅=A∪B={1;2;4}


b)B\C=B
B∪(A∩B)=B={1;4}

c) C\A=C
A\B={2}
C∪{2}={0;2;7}

d)B∪C={0;1;4;7}
A\C=A
{0;1;4;7}∩A= {0;1;4;7}∩{1;2}={1}
Obs In acesta caz A\C=A si C\A=C pt ca A∩C=∅
analog B∩C=∅ si M\∅+M, oricare ar fi multimea M
am folosit aceste proprietati pt a scurta calculele