Question

Rezolvati exercitiul 13 punctul a)

Answer 1

Al 2-lea e mai mare . 
Sper ca te-am ajutat :D

Answer 2

$(8^1^3 \cdot 4^1^5)^3=[(2^3)^1^3 \cdot (2^2)^1^5]^3=(2^3^9 \cdot 2^3^0)^3= (2^{39+30})^3= \\ =(2^6^9)^3=2^2^0^7 \\ (81^9 \cdot 27^7)^2 \cdot (3^8)^3=[(3^4)^9 \cdot (3^3)^7]^2 \cdot 3^2^4=(3^3^6 \cdot 3^2^1)^2 \cdot 3^2^4= \\ =(3^{36+21})^2 \cdot 3^2^4=(3^5^7)^2 \cdot 3^2^4=3^1^1^4 \cdot 3^2^4=3^{114+24}=3^1^3^8 \\ 2^{207}=(2^3)^6^9=8^6^9 \\ 3^1^3^8=(3^2)^6^9=9^6^9 \\ 8\ \textless \ 9 \Rightarrow 8^6^9\ \textless \ 9^6^9 \Rightarrow 3^1^3^8\ \textgreater \ 2^2^0^7$