Question

REZOLVATI EXERCITIUL (4X2)+(5X2)+6000+3000+584 CALCULEAZA a+b+c,stiind ca a=1354+1846 b=3638+383 c=564+649+855 Problema Intr-o livada erau 2130 de pomi fructiferi.Nuci si peri erau 1040,iar meri cu 590 mai multi decat nuci. Cati pomi de fiecare fel sunt? ofer coroana

Answer 1

(4×2)+(5×2)+6000+3000+584=8+10+9584=9602



a=1354+1846=3200
b=3638+383=4021
c=564+649+855 =2068
a+b+c=3200+4021+2068=9289

Intr-o livada erau 2130 de pomi fructiferi.Nuci si peri erau 1040,iar meri cu 590 mai multi decat nuci. Cati pomi de fiecare fel sunt?
n=nuci
m=meri
p=peri
n+p=1040
m=n+590
m+n+p=2130
m=2130-(n+p)=2130-1040=1090
n=m-590=1090-590=500
p=1040-n=1040-500=540

Answer 2

1) 9602 ; 2) 9289 ; 3) 1090 meri , 500 nuci , 540 peri ( Explicatie : n + p = 1040 ; toti pomii = 2130  atunci m e diferenta , adica 1090. m = n + 590. deci n = 500 . si ultimii , p = 540 adica ce ramane )