Question

rezolvati i R ecuatia :
a)5-4(2x+3) ≥ 1-2(3x-7)
b)12x-(x+4)≤ -3-(x-2)

Answer 1

a) 5-8x-12 > sau = 1-6x+14

-8x+6x > sau = -5+12+14

-2x > sau = 21

-x > sau = 10,5

- x e { 10,5, 11, 12, etc.}

b) 12x- x- 4 < sau = -3-x+2

12x -x+ x < sau = 4-3+2

-x cu +x se reduc

12x < sau = 3

x < sau = 3/12= 1/4

x e {0,25; 0,24 ; etc}