Question

Rezolvati in C ecuația (z+1)^2+1=0

Answer 1

(z+1)²+1=0

=> (z+1)² = -1

Notam z+1 = t => t² = -1

$t_1 = i, \quad \quad t_2 = - i$

(1) z+1 = i => z = -1+i
(2) z+1 = -i => z = -1-i

S = {-1+i, -1-i}