Question

Rezolvati in multimea N ecuatia: a) 60:(3y+2)=12. b)1-3(8x-4)=1

Answer 1

$\displaystyle a).60:(3y+2)=12 \\ 3y+2=60:12 \\ 3y+2=5 \\ 3y=5-2 \\ 3y=3 \\ y=3:3 \\ y=1 \\ b).1-3(8x-4)=1 \\ 1-24x+12=1 \\ -24x=1-1-12 \\ -24x=-12 \\ x= \frac{12}{24} \Rightarrow x= \frac{1}{2}$