Question

rezolvati in multimea nr reale ecuatia: radical din x^2 -2x+16=4

3log4(3x+1)=6

3x^(x+2) + 3^x=30
URGENT!!!!

Answer 1

$\it 3log_4(3x+1)=6|_{:3} \Rightarrow log_4(3x+1)=2 \Rightarrow 3x+1=4^2 \Rightarrow 3x+1=16|_{-1} \Rightarrow \\ \\ \Rightarrow 3x=15|_{:3} \Rightarrow x=5\\ \\ (Verificarea\ \ este\ \ imediat\breve a)$

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