Question

Rezolvati in multimea nr reale ecuatia: $2*2^x=4^x^-^2$

Answer 1

$2*2^x= 4^{x-2} \\ 2*2^x= 2^{2x}* 4^{-2} \\ 2^x=t;t\ \textgreater \ 0 \\ \frac{t^2}{16}-2t=0 \\ t^2-32t=0 \\ t(t-32)=0 \\ t=0 ;t=32 \\ revenim \\ 2^x=32 \\ adica \\ 2^x=2^5 \\ x=5$