Question

Rezolvati in mulțimea numerelor ecuația:
3•{10+2•[40-2•(28-3•5)]}-7x=51
Vă rog repede dau coroniță.

Answer 1

3•{10+2•[40-2•(28-3•5)]}-7x=51
3•{10+2•[40-2•(28-15)]}-7x=51
3•[10+2•(40-2•13)]-7x=51
3•[10+2•(40-26)]-7x=51
3•(10+2•14)-7x=51
3•(10+28)-7x=51
3•38-7x=51
114-7x=51
7x=114-51
7x=63
x=63:7
x=9

Answer 2

10+2*[40-2*(28-15)]-7x=51:3
=17
2*(40-2*13)-7x=17-10
2*(40-26)-7x=7
14-7x=7:2
14-7x=3,5
14-(-3,5)=7x
14+3,5=7x
17,5=7x=>x=17,5:7=2,5
Imi dai coroana???