Question

Rezolvați în mulțimea numerelor întregi ecuațiile​

Answer 1

Răspuns:

a)2(x+1)= -7(x+3)+3(3x-5)-5=

2x+2= -7x-21+9x-15-5

2x+2=2x-41

2x-2x=-39

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b) -3(3x+1)+14=3(7x-3)-10

-9x-3+14=21x-9-10

-9x+11=21x-19

11+19=21x+9x

30=20x

x=30/20

x=3/2

c)14+2[3-2(x-3)]:2=37

14+2(3-2x+6):2=37

14+3-2x+6=37

14+9-2x=37

23-2x=37

-2x=37-23

-2x=14

x=14/ -2

x=-7

d)-4-{6-[-3+(-3)+(-5-x)-7]-9}=1

-4-[6-(-3-3-5-x-7)-9]=1

-4-(6+18-x-9)=1

-4-(6+9-x)=1

-4-6-9+x=1

-19+x=1

x=1+19

x=20

e)5(7x-1)⁰+2(x+1)= -7(x+3)+3(3x-5)+43

5×1+2x+2= -7x-21+9x-15+43

5+2x+2= 2x-36+43

7+2x=2x-7

2x-2x=-7-7

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