Question

Rezolvati in multimea numerelor naturale ecuatiile   a](x-1)(x+3)=0 
b]( 3x-6)(4x-3)=0 
c](x+2)(x+3)=12
d]$x^{2}$+x=6

Answer 1

a)(x-1)(x+3)=0
x-1=0
x₁=1
x+3=0
x₂=-3
x∈{-3,1}
b)(3x-6)(4x-3)=0
3x-6=0
3x=6
x₁=6/3=2
4x-3=0
4x=3
x₂=3/4
x∈(3/4,2}
c)(x+2)(x+3)=12
x²+3x+2x+6-12=0
x²+5x-6=0
(2x-1)(2x+7)=0
2x-1=0
2x=1
x=1/2
2x+7=0
2x=-7
x=-7/2
x∈{-7/2,1/2}
d)x²+x=6
x²+x-6=0
(x-2)(x+3)=0
x-2=0
x=2
x+3=0
x=-3
x∈{2,3}