Question

rezolvati in multimea numerelor naturale inecuatiile:
7(2x-1)<_ 49 si 6(2x+3)-4<_38
Ajutor dau 30 puncte coroană si mulțumesc!!!!

Answer 1

7(2x-1)<_ 49

14x-7<_49

14x<_56

x<_4, x=natural, deci x=0,1,2,3,4

6(2x+3)-4<_38 

12x+18-4<_38

12x+14<_38

12x<_24

x<_2, x=natural, deci x=0,1,2

Answer 2

∅ Rezolvare : a ) 7( 2x - 1 ) ≤ 49 => 14x - 7 ≤ 49 => 14x ≤ 49 + 7 => 14x ≤ 56 => x ≤ 56 : 14 => x ≤ 4 => S = { 0 , 1 , 2 , 3 , 4 } b ) 6( 2x + 3 ) - 4 ≤ 38 => 12x + 18 - 4 ≤ 38 => 12x ≤ 38 + 4 - 18 => 12x ≤ 42 - 18 => 12x ≤ 24 => x ≤ 24 : 12 => x ≤ 2 => S = { 0 , 1 , 2 }