Question

Rezolvati in multimea numerelor naturale urmatoarea ecuatie:
2(x+1)² + 3(x-2) ≥ 3(x+2)(x-2) - (x² - 8x).

Answer 1

$2x^{2} +4x+2+3x-6 \geq 3x^{2} -3* 2^{2} -x+8x$
$2x^{2} +7x-4 \geq 3 x^{2} -12-x+8x$
$-4+12 \geq 3 x^{2} -2 x^{2} +7x-7x$
$8 \geq x^{2}$
x=1
x=2