Question

Rezolvati in multimea numerelor rationale ecuatiile:
b)(x+3)(x-1)=(x+3)²+8;
c)(x-1)²-x(x+5)=3x+7;
d)(x+3)(x-3)+2x=(x+4)²+5;
e)(x+1)²-3(x+7)=3+(x-2)²;
f)(x+2)(x-2)+4(x+3)=(x+2)²-3x.
VA ROG MA AJUTATI????

Answer 1

b)
${ x}^{2} + x + 3x - 3 = {x}^{2} + 6x + 9 + 8 \\ {x}^{2} + 4x - 3 = {x}^{2} + 6x + 17 \\ {x}^{2} - {x}^{2} + 4x - 6x = 17 + 3 \\ - 2x = 20 \\ x = - 10$
c)
${x}^{2} + 2x + 1 - {x}^{2} - 5x = 3x + 7 \\ - 3x - 3x = 7 \\ - 6x = 7 \\ x = - \frac{7}{6}$
d)
${x}^{2} - 9 + 2x = {x}^{2} + 8x + 16 + 5 \\ {x}^{2} - {x}^{2} + 2x - 8x = 21 - 9 \\ - 6x = 12 \\ x = - 2$
e)
${x}^{2} + 2x + 1 - 3x - 21 = 3 + {x}^{2} - 4x + 4 \\ {x}^{2} + 2x - 3x - {x}^{2} + 4x = 4 - 1 + 21 \\ 3x = 24 \\ x = 8$
f)
${x}^{2} - 4 + 4x + 12 = {x}^{2} + 4x + 4 - 3x \\ {x}^{2} + 4x - {x}^{2} - 4x + 3x = 4 + 4 - 12 \\ 3x = 4 \\ x = \frac{4}{3}$
Sper că te am ajutat,primesc coroană?