Question

Rezolvati in multimea numerelor reale ecuatia log baza 7($x^{2}$+8)=log baza7 (6x)

Answer 1

[tex]Conditii\ de\ existenta:6x>0=>x>0\\ log_7(x^2+8)=log_7(6x)\\ x^2+8=6x\\ x^2-6x+8=0\\ \triangle=36-32=4\\ x_{1/2}= \frac{6\pm 2}{2} \\ x_1=4\\ x_2=2[/tex]