Question

Rezolvati in multimea numerelor reale ecuatia : $\frac{ (x-2)^{2} }{2}+ x(x-1) = \frac{3x(x-5)}{2}+12$

Answer 1

$( x-2)^{2} +2x(x-1)=3x(x-5)+24$
$x^{2} -2x+4 +2x^{2} -2x-3 x^{2} +5x=24$
$3x^{2}-3 x^{2} -4x+ 5x=24-4$
$x=20$