Question

rezolvati in multimea numerelor reale$\sqrt {2x^{2}+1= 1$

\sqrt {2x^{2}+1= 1

Answer 1

2x²+1>0∀x=>√(2x²+1)>0  Ridici egalitatea  la   patrat
2x²+1=1=> 2x²=0  =>  x=0