Rezolvati in multimea numerelor reale urmatoarea ecuatie:
4/3+2(x-3)=2x+7/10-4x+3/15+1/30
/=linie de fractie
Repede!!
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4/3+2(x-3)=2x+7/10-4x+3/15+1/30
4/3+2x-6=2x+7/10-4x+3/15+1/30
4/3-6=+7/10-4x+3/15+1/30
40-180=21-120x+6+1
120x=28+140
120x=168
x=168/120
x=7/5
4/3+2x-6=2x+7/10-4x+3/15+1/30
4/3-6=+7/10-4x+3/15+1/30
40-180=21-120x+6+1
120x=28+140
120x=168
x=168/120
x=7/5
7Deniii7:
poti sa o mai faci o data? era 4/3+2(x-3)/5=2x+7/10-4x+3/15+1/30
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