Question

Rezolvați in mulțimea numerelor reale următoarele ecuatii:2X(radical 3+radical2)-radical2(3+2X)=radical3(X+radical2)

Answer 1

2x(√3+√2) - √2(3+2x) = √3(x+√2)

2√3·x + 2√2·x - 2√3 - 2√2·x = √3·x + √6

2√3·x - √3·x = √6 - 2√3

√3·x = √6 - 2√3

x = (√6 - 2√3)/√3

x = √3(√6 - 2√3)/3

x = (√18 - 6)/3

x = (3√2 - 6)/3

x = 3(√2 - 2)/3

x = √2 - 2