Matematică, întrebare adresată de diaconuv401, 9 ani în urmă

Rezolvati in multimea Q ecuatiile: a)4x+12=3x+8 b)3x-17=8x+18 c)4/5x+1intreg 2/5x=2/5x-2intreg 3/5 d)2intreg 2/5x+3intreg 2/15=3intreg 1/5x+2intreg 1/3 Va rog mult urgent!

Răspunsuri la întrebare

Răspuns de samsunggenius200
3
a) 4x+12=3x+8
4x+12−3x=3x+8−3x+12=8
x+12−12=8−12x=4

b) 
3x−17=8x+18
3x−17−8x=8x+18−8x−5x−17=18
−5x−17+17=18+17−5x=35
 \frac{-5x}{-5} = \frac{35}{-5}
x=7

c)  \frac{4}{5x} +1 \frac{2}{5x} = \frac{2}{5x} -2 \frac{3}{5}
 \frac{6}{5x} = \frac{-13x+2}{5x}
6*5x=(−13x+2)*(5x)30x=65x2+10x
30x−(−65x²+10x)=−65x²+10x−(−65x+10x)65x²+20x=05x(13x+4)=0
5x=0 or 13x+4=0
x=0 or x= \frac{-4}{13}

d) 
2 \frac{2}{5x} +3 \frac{2}{15} =3 \frac{1}{5x} +2 \frac{1}{3}
 \frac{47x+12}{15x} = \frac{35x+9}{15x}
(47x+12)*(15x)=(35x+9)*(15x)705x²+180x=525x²+135x
705x²+180x−(525x²+135x)=525x²+135x−(525x²+135x)180x²+45x=0
45x(4x+1)=0
45x=0 or 4x+1=0
x=0 or x= \frac{-1}{4}
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