Question

rezolvati in multirea numerelor naturale inecuatiile:
3*(y+21)<64

Answer 1

3(y+21)<64
3y+63<64
3y<64-63
3y<1
y<1/3
x∈(-α, 1/3}

Answer 2

3y+63<64
3y<64-63
y<1/3
y∈{1/2...∞}