Question

Rezolvati in N ecuatiile a) 5x+11= 371, b) (24+x): 25=15, c) 3 la puterea a 2 ×[3 la puterea a 2 ×(x:3 la puterea a 2 -222)+1 la puterea 0]+1 la puterea a 1999=10

Answer 1

a) 5x+11=371
5x=371-11
5x=360
x=360:5
x=72
b) (24+x):25=15 

24/25 +x/25 =15*25/25
24+x=375 
x=351
C) 9*[9*(x:9-222)+1]+1=10

si faci calculu 

Answer 2

a) 5x+11=371
5x=371-11
5x=360
x=72
b) (24+x):25=15
24+x=15x25
24+x=375
x=375-24
x=351
Verificare (24+351):25=15
              375:25=15
                    15=15
c) 3²x {3²x(x:3²-222)+1]+1 la puterea 1999=10

9x[9x(x:9-222)+1]+1 =10
9x[9x(x-222x9)+1]+1=10
9x[9x(x-1998)+1]+1=10
9x(9x - 1998*9+1)+1=10
9x(9x-17982+1)+1=10
9x(9x-17981)+1=10
81x-17981*9+1=10
81x-161829+1=10
81x-161828=10
81x=10+161828
81x=161838
x-168383/81
x=1998