Question

Rezolvați, în numere naturale:
23 la 2x-1<23 la x+8;
15 la 9>15 la x+2

Answer 1

[tex]23^{2x-1}\ \textless \ 23^{x+8}\\ 2x-1\ \textless \ x+8\\ 2x-x\ \textless \ 8+1\\ x\ \textless \ 9\\ x\in \{0,1,...,8\}[/tex]
[tex]15^9\ \textgreater \ 15^{x+2}\\ 9\ \textgreater \ x+2\\ x+2\ \textless \ 9\\ x\ \textless \ 9-2\\ x\ \textless \ 7\\ x \in \{0,1,2,...6\}[/tex]