Question

Rezolvati in numere rationale ecuatile: a) 2x-3 supra 5=x-1 supra 3. b)×-3×-2supra 7=2. c) 3x-5 supra 4-x-7 supra 6=1+×-5 supra3.Va rog !!!

Answer 1

a) (2x-3)/5 = (x-1)/3  ]·15
3(2x-3) = 5(x-1)    6x -9 = 5x - 5      x = 4
b)    x - (3x-2)/7 = 2  ]·7    7x - 3x + 2 = 14    4x = 12      x = 3
c)  (3x-5)/4  - (x-7)/6 = 1 + (x-5)/3    ]·12
3(3x - 5) - 2(x-7) = 12 + 4(x-5)
9x - 15 - 2x + 14 = 12 +4x -20
3x = - 7       x = - 7/3