Question

rezolvati in Q ecuatia 5/3x-0,(6)=0,25x+1

Answer 1

Rezolvati in Q ecuatia:
[tex] \frac{5x}{3} [/tex] - 0,(6)= 0,25x+1
$\frac{5x}{3}$ - $\frac{6}{9}$=$\frac{25x}{100}$+1
$\frac{5x}{3}$ - $\frac{2}{3}$=$\frac{x}{4}$ +1
[tex] \frac{5x}{3} [/tex] - $\frac{x}{4}$=1+$\frac{2}{3}$ |*12
5x*4+ 3x=12+8
20x+3x=20
23x=20
x=$\frac{20}{23}$