Question

Rezolvati in Q+ ecuatia:
Dau COROANA+ma abonez

Answer 1

2x/3+1/2=3/4

Amplifici prima fractie cu 2 și pe a doua cu 3 și avem:

(4x+3)/6=3/4

(4x+3)4=18

16x+12=18

16x=18-12

16x=6

x=6/16

x=3/8

Answer 2

$\dfrac{2}{3}\cdot x +\dfrac{1}{2} = \dfrac{3}{4}\Big|\cdot 3\cdot 2\cdot 4\\ \\ \Rightarrow (3\cdot 2\cdot 4)\cdot \dfrac{2}{3}\cdot x+(3\cdot 2\cdot 4)\cdot \dfrac{1}{2} = (3\cdot 2\cdot 4)\cdot \dfrac{3}{4}\\ \\ \Rightarrow (2\cdot 4)\cdot 2\cdot x + (3\cdot 4)\cdot 1 = (3\cdot 2)\cdot 3\\ \\ \Rightarrow 16x+12 = 18\\ \\ \Rightarrow 16x = 18-12\\ \\ \Rightarrow 16x = 6\\ \\ \Rightarrow x = \dfrac{6}{16}\\ \\ \Rightarrow \boxed{x = \dfrac{3}{8}}$