Question

rezolvati in Q ecuatia de mai sus

Answer 1

[tex]\it In \ membrul \ drept\ d\breve{a}m\ factor\ comun\ \dfrac{1}{3},\ iar\ ecua\c{\it t}ia\ devine: \\ \\ \\ \dfrac{1}{3}\left(\dfrac{1}{22}+\dfrac{1}{202}+\ ...\ +\dfrac{1}{2\underbrace{000...0}_{2014\ zerouri}2}\right)x=\dfrac{1}{22}+\dfrac{1}{202}+\ ...\ +\dfrac{1}{2\underbrace{000...0}_{2014\ zerouri}2}[/tex]

[tex]\it Imp\breve{a}r\c{\it t}im\ la\ suma\ din\ parantez\breve{a},\ iar\ ecua\c{\it t}ia\ devine: \\ \\ \\ \dfrac{1}{3}x = 1 \Rightarrow \dfrac{x}{3} = 1 \Rightarrow x = 3[/tex]