Question

Rezolvati in Q ecuatia:

$2,(3)x+1 \frac{1}{6} =0,(6)x+2 \frac{1}{3}$

Answer 1

21x supra 9+7 supra 6=6x supra 9+7 supra 3
42x supra 18+21 supra 18=12x supra 18+42 supra 18
42x+21=12x+42
30x=21 deci x=0,7

Answer 2

$\displaystyle 2,(3)x+1 \frac{1}{6} =0,(6)x+2 \frac{1}{3} \\ \frac{23-2}{9} x+ \frac{1 \cdot 6+1}{6} = \frac{6}{9} x+ \frac{2 \cdot 3+1}{3} \\ \frac{21}{9}x + \frac{7}{6} = \frac{6}{9} x+ \frac{7}{3} \\ 21x \cdot 2+7 \cdot 3=6x \cdot 2+7 \cdot 6 \\ 42x+21=12x+42 \\ 42x-12x=42-21 \\ 30x=21 \\ x= \frac{21}{30} \Rightarrow x= \frac{7}{10}$