Question

Rezolvati in Q ecuatia:$\frac{1-3x}{36-x^2} - \frac{x}{x+6} =-1$ ajutatima va rog

Answer 1

(1-3x)/(6-x)(6+x)-x/(x+6)+1=0, eliminam numitorul 1-3x-x(6-x)+36-x patrat=0=>     1-3x-6x+x patrat+36-xpatrat=0=> -9x+37=0=>9x=37=>x=37/9