Question

REZOLVATI IN Q ECUAȚIE .Vă rog eu frumos dau coronița

Answer 1

$\frac{5}{6}$×(x-3$\frac{1}{3}$×1$\frac{1}{5}$)=2$\frac{3}{4}$+3÷1$\frac{2}{3}$ ⇔ $\frac{5}{6}$×(x-$\frac{10}{3}$×$\frac{6}{5}$)=$\frac{11}{4}$+$\frac{5}{4}$÷$\frac{5}{3}$⇔$\frac{5}{6}$×(x-2×2)=$\frac{11}{4}$+$\frac{15}{4}$×$\frac{3}{5}$⇔$\frac{5}{6}$×(x-4)=$\frac{11}{4}$+$\frac{3}{4}$×$\frac{3}{5}$⇔$\frac{5}{6}$x-$\frac{10}{3}$=5⇔5x-20=30⇔5x=50⇔x=10

($\frac{15}{16}$*2$\frac{6}{25}$-1$\frac{1}{2}$)×(x+$\frac{1}{2}$=2$\frac{1}{3}$-$\frac{5}{6}$⇔$(\frac{3}{2} *\frac{7}{5} - \frac{3}{2} )*(x+\frac{1}{2} )=\frac{3}{2}$⇔$\frac{3}{5} * (x+\frac{1}{2} )=\frac{3}{2}$⇔6x+3=15⇔6x=12⇔x=2

$(5\frac{1}{2} *x-3\frac{2}{4} )*\frac{6}{5} = 2\frac{2}{5}\\(\frac{11}{2} x-\frac{7}{2} )* \frac{6}{5} = \frac{12}{5} \\33x-21=12\\33x=33\\x=1$

$3\frac{3}{5}*(4 \frac{1}{4} /3\frac{2}{5} -x*1\frac{5}{9} ) = \frac{2}{3} * (\frac{1}{4} + \frac{1}{5} )\\\frac{18}{5} *( \frac{17}{4} *\frac{5}{7} -\frac{14}{9} x )=\frac{3}{10} \\\frac{18}{5} (\frac{5}{4} -\frac{14}{9}x)= \frac{3}{10} \\45-56x=3\\-56x=-42\\x=\frac{3}{4}$

$\frac{1}{3} *(x+\frac{1}{2} ) -0,5(2x+\frac{1}{3} )=2(\frac{x}{3} +1\frac{1}{4})\\\frac{1}{3} x +\frac{1}{6} -x - \frac{1}{6} =\frac{2x}{3}+ \frac{5}{2}\\2x-6x=4x+15\\-4x-4x=15\\x=-\frac{15}{8}$

$\frac{1}{5} *(\frac{3x}{2} -1)+\frac{3x}{2} =\frac{4x+1}{5} \\3x-2+15x=2(4x+1)\\18x-8x=2+2\\x=\frac{2}{5}$