Question

rezolvati in Q ecuatiile:
a)
$\frac{4x + 7}{5} - \frac{3x + 2}{2} = \frac{4}{5} (3x - 4) - 1 \frac{1}{2} (x - 3)$
b)
$\frac{3}{7} (x + 4) - \frac{2x + 9}{2 } = 1 \frac{1}{7} (x + 5) - 1 \frac{2}{3} (x + 3)$
c)
$2 \frac{1}{5} - \frac{4(x + 1)}{3} + \frac{7x + 4}{5 } + \frac{2(x + 3)}{5} - \frac{2x + 5}{3}$
d)
$\frac{ - 2(x + 5)}{6} + \frac{3(2x + 1)}{7} = \frac{ - 5(x + 1)}{14} + \frac{3x - 3}{21}$
vă rogg
​

Answer 1

raspuns:

am atasat poza

explicatie:

La b am sarit un pas si am scris direct,iti dai seama unde ,pt ca e la fel ca la a .Nu am putut sa fac c si d ,scuze.Sper ca te am ajutat oricum...