Question

Rezolvați în Q ecuațiile :a) x+7/3=2/9
b) 4/5x-3/10x=-3
C)x/3+5-x/9-x/27-2/3=1/9
ajutatima dau coroană

Answer 1

a) x+7/3=2/9
18x+42=4
18x=4-42
x=-38/18
x=-19/9
b) 4/5x-3/10x=-3
8x-3x=-30
5x=-30
x=-30/5
x=-6
c) x/3+5-x/9-x/27-2/3=1/9
9x+135-3x-x-18=3
5x=3-117
x=-114/5

Answer 2

$\displaystyle a).x+ \frac{7}{3} = \frac{2}{9} \Rightarrow 9x+7 \cdot 3=2 \Rightarrow 9x+21=2 \Rightarrow 9x=2-21 \Rightarrow \\ \\ \Rightarrow 9x=-19 \Rightarrow x=- \frac{19}{9} \\ \\ b). \frac{4}{5}x- \frac{3}{10} x=-3 \Rightarrow 4x \cdot 2-3x=-3 \cdot 10 \Rightarrow 8x-3x=-30 \Rightarrow \\ \\ \Rightarrow 5x=-30 \Rightarrow x=- \frac{30}{5} \Rightarrow x=-6$

$\displaystyle c). \frac{x}{3}+5- \frac{x}{9}- \frac{x}{27} - \frac{2}{3} = \frac{1}{9} \Rightarrow 9x+5 \cdot 27-3x-x-2 \cdot 9=1 \cdot 3 \Rightarrow \\ \\ \Rightarrow 9x+135-3x-x-18=3 \Rightarrow 9x-3x-x=3-135+18 \Rightarrow \\ \\ \Rightarrow 5x=-114 \Rightarrow x=- \frac{114}{5}$