Question

Rezolvati in Q ecuatiile : x²=49 ; x²=25pe81; 4x²=9 pe 32

Answer 1

$x^{2} =49 x= \sqrt{49} x=7$

[tex] x^{2} =25/81
 x= \sqrt{25/81}
 x=5/9[/tex]


[tex]4 x^{2} = \frac{9}{32 4 x^{2} *32=9 128 x^{2} =9 x^{2} =9/128 x= \sqrt{ \frac{9}{128} }= \frac{3}{ \sqrt{4*32} } =3/2* \sqrt{32} } [/tex]