Question

rezolvati in Q ecuatile.  a) 2(x+1/5)=7/4           b)1,(3)*(3x-0,75)=1/3

Answer 1

a)2( x+1/5)=7/4     aducem la acelasi numitor in paranteza

2 (5x+1)/5=7/4

(10x+2)/5=7/4

4(10x+2)=5*7
40x+8=35

40x=35-8
40x=27

x=27/40

b)1,(3)=1 intreg 3/9=  1 intreg  1/3=  4/3
0,75=75/100=3/4

4/3 * (3x-3/4)=1/3   aducem la acelasi numitor in paranteza

4/3 * (12x-3)/4=1/3

(12x-3)/3=1/3

12x-3=1

12x=1+3

12x=4

x=4/12= 1/3