Question

rezolvati in r ecuatia 4x^-12x+9=0

Answer 1

$4 {x}^{2} - 12x + 9 = 0$

$a = 4$

$b = - 12$

$c = 9$

$\Delta={b}^{2}-4ac$

$\Delta={( - 12)}^{2}-4 \times 4 \times 9$

$\Delta=144-144 = 0$

$\Delta=0 \: = > x_{1} = x_{2}$

$x_{1} = x_{2} = \frac{ - b + \sqrt{\Delta}}{2a} = \frac{ - ( - 12) + 0}{2 \times 4} = \frac{12}{8} = \frac{3}{2} \: \epsilon \: R$