Question

Rezolvati in R ecuatia:
a) 5x²+0,2x=0
b) 5x²-6x+1=0
c) 3x(3x-2)+7=6
urgentttttttt

Answer 1

a)5x²+0.2x=0
a=5
b=0.2
c=0
Δ=b²-4ac⇒Δ=(0.2)²-4×5×0⇒Δ=0.04⇒√Δ=√0.04⇒0.2
x1x2=-b+-√Δ/2a⇒
x1=-0.2+0.2/2×5⇒0/10⇒x1=0
x2=-0.2-0.2/10⇒-0.4/10⇒x2=0.2/0.5
b)5x²-6x+1=0
a=5
b=-6
c=1
Δ=b²-4ac⇒Δ=(-6)²-4×5×1⇒36-20⇒Δ=16⇒√Δ=√16⇒Δ=4
x1x2=-b+-√Δ/2a⇒
x1=6+6/10⇒12/10⇒x1=6/5
x2=6-6/10⇒0/10⇒x2=0

3x(3x-2)+7=6
9x²-6x+7=6⇒9x²-6x+7-6=0⇒9x²-6x+1=0
a=9
b=-6
c=1
Δ=b²-4ac⇒Δ=36-36⇒Δ=0
x1x2=-b+-√Δ/2a⇒
x1x2=6-+0/9=6/9⇒x1x2=2/3
sucees