Question

Rezolvati in R ecuatia
Dau coroana
Punctul 1, urgent

Answer 1

(x² + x - 2)/(x + 2) = (4x - 4)/3

3x² + 3x - 6 = (x + 2)(4x - 4)

3x² + 3x - 6 = 4x² + 8x + -4x - 8

4x² - 3x² + 8x - 5x - 8 + 6 = 0

x² + 3x - 2 = 0

x = (- 3 ±√3² - 4×1×(-2))/2×1

= (- 3 ± √17)/2

x₁ = (- 3 + √17)/2

x₂ = (- 3 - √17)/2

Answer 2

$\it \dfrac{x^2+x-2}{x+2}=\dfrac{4x-4}{3} \Rightarrow \dfrac{x^2+2x-x-2}{x+2}=\dfrac{4(x-1)}{3} \Rightarrow \\ \\ \\ \Rightarrow \dfrac{x(x+2)-(x+2)}{x+2}=\dfrac{4(x-1)}{3} \Rightarrow \dfrac{(x+2)(x-1)}{x+2}=\dfrac{4(x-1)}{3} \Rightarrow\\ \\ \\ \Rightarrow x-1=\dfrac{4(x-1)}{3}|_{\cdot3} \Rightarrow 3(x-1)=4(x-1) \Rightarrow 0=4(x-1)-3(x-1)\Rightarrow\\ \\ \\ \Rightarrow 0=x-1\Rightarrow x=1$