Question

Rezolvati in R ecuatia :e)(x-2)(x+3)=24

Answer 1

[tex] x^{2} +3x-2x-6=24 x^{2} +x-6=24 x^{2} +x-30=0 a=1 b=1 c=-30 D= b^{2} -4ac D=1+120 D=121 x_{1} = \frac{-b +\sqrt{d} }{2a} =-1+11/2=5 x_{2} = \frac{-b -\sqrt{d} }{2a} =-1-11/2=-6 Sol:(5,-6) [/tex]