Question

Rezolvati in R ecuatia radical de ordin 3 din x+2 +2 = 0.
(doar x+2 este sub radical)​

Answer 1

$\sqrt[3]{x + 2} + 2 = 0 \\ \\ \sqrt[3]{x + 2} + 2 - 2 = 0 - 2 \\ \\ \sqrt[3]{x + 2} = 0 - 2 \\ \\ \sqrt[3]{x + 2} = - 2 \\ \\ \sqrt[3]{x + 2} ^{3} = {( - 2)}^{3} \\ \\ x + 2 = - {2}^{3} \\ \\ x + 2 = - 8 \\ \\ x + 2 - 2 = - 8 - 2 \\ \\ x = - 8 - 2 \\ \\ x = - (8 + 2) \\ \\ x = - 10$