Question

Rezolvati in R ecuatia:

$\frac{1}{t-8} + \frac{1}{t-6} + \frac{1}{t+6} + \frac{1}{t+8} =0$

Answer 1

1/(t-8)+1/(t-6)+1/(t+6)+1/(t+8)=0
(t−6)(t+6)(t+8)+(t−8)(t+6)(t+8)+(t−8)(t−6)(t+8)+(t−8)(t−6)(t+6)=
4t^3-200t=0
4t(t^2-50)=0 => 4t=0 => t= 0; t= 5√2; t= -5√2